Genotypic Frequency of Heterozygote in Hardy-Weinberg Equilibrium
If gene frequency of A = 0.7 and a = 0.3, what is the genotypic frequency of the heterozygote (Aa)?
- 0.42 — Correct Answer
- 0.21
- 0.49
- 0.09
Explanation:
Correct Answer: 0.42
Using the Hardy-Weinberg equation, the genotypic frequency of the heterozygote (Aa) = 2pq.
Calculation
- p = 0.7 (frequency of A)
- q = 0.3 (frequency of a)
- Frequency of Aa = 2pq = 2 × 0.7 × 0.3 = 0.42
Complete Genotypic Frequencies
| Genotype | Frequency | Value |
|---|---|---|
| AA | p² = (0.7)² | 0.49 |
| Aa | 2pq = 2×0.7×0.3 | 0.42 |
| aa | q² = (0.3)² | 0.09 |
| Total | p² + 2pq + q² = 1 | 1.00 |
Maximum heterozygote frequency (0.50) occurs when p = q = 0.5.
📚 About this Topic — Animal Genetics & Breeding
This multiple choice question is from Animal Genetics & Breeding, Animal Refresher. It has 4 options with a detailed explanation of the correct answer. Practice more MCQs from Animal Genetics & Breeding to strengthen your preparation.
