Genotypic Frequency of Heterozygote in HW Equilibrium
If gene frequency of A = 0.7 and gene frequency of a = 0.3, the genotypic frequency of heterozygote (Aa) under Hardy-Weinberg equilibrium is:
- 0.49
- 0.21
- 0.42 — Correct Answer
- 0.09
Explanation:
Correct Answer: 0.42
Genotypic frequency of heterozygote = 2pq = 2 × 0.7 × 0.3 = 0.42
Hardy-Weinberg Genotypic Frequencies
- Freq(AA) = p² = (0.7)² = 0.49
- Freq(Aa) = 2pq = 2 × 0.7 × 0.3 = 0.42
- Freq(aa) = q² = (0.3)² = 0.09
- Check: 0.49 + 0.42 + 0.09 = 1.00 ✓
Important note: Frequency of heterozygotes (2pq) cannot exceed 50% and is maximum when p = q = 0.5, giving 2pq = 0.50.
📚 About this Topic — Animal Genetics & Breeding
This multiple choice question is from Animal Genetics & Breeding, Animal Refresher. It has 4 options with a detailed explanation of the correct answer. Practice more MCQs from Animal Genetics & Breeding to strengthen your preparation.
